\(4x^4 - 8x^2 - 5x\) divided by \(x -3\) is \(4x^3 + 12x^2 + 28x + 79\) with remainder 237. Then f (t) = g (t) for all t 0 where both functions are continuous. % Lemma : Let f: C rightarrowC represent any polynomial function. Please get in touch with us, LCM of 3 and 4, and How to Find Least Common Multiple. 3.4 Factor Theorem and Remainder Theorem 199 Finally, take the 2 in the divisor times the 7 to get 14, and add it to the 14 to get 0. . Divide \(x^{3} +4x^{2} -5x-14\) by \(x-2\). According to the principle of Remainder Theorem: If we divide a polynomial f(x) by (x - M), the remainder of that division is equal to f(c). Sub- We then Here is a set of practice problems to accompany the The Mean Value Theorem section of the Applications of Derivatives chapter of the notes for Paul Dawkins Calculus I course at Lamar University. If (x-c) is a factor of f(x), then the remainder must be zero. 434 0 obj
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The possibilities are 3 and 1. r 1 6 10 3 3 1 9 37 114 -3 1 3 1 0 There is a root at x = -3. Rs 9000, Learn one-to-one with a teacher for a personalised experience, Confidence-building & personalised learning courses for Class LKG-8 students, Get class-wise, author-wise, & board-wise free study material for exam preparation, Get class-wise, subject-wise, & location-wise online tuition for exam preparation, Know about our results, initiatives, resources, events, and much more, Creating a safe learning environment for every child, Helps in learning for Children affected by 10 Math Problems officially announces the release of Quick Math Solver, an Android App on the Google Play Store for students around the world. 0000008188 00000 n
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The quotient obtained is called as depressed polynomial when the polynomial is divided by one of its binomial factors. 9s:bJ2nv,g`ZPecYY8HMp6. Factor Theorem. As a result, (x-c) is a factor of the polynomialf(x). Remainder Theorem states that if polynomial (x) is divided by a linear binomial of the for (x - a) then the remainder will be (a). endobj
This theorem is used primarily to remove the known zeros from polynomials leaving all unknown zeros unimpaired, thus by finding the zeros easily to produce the lower degree polynomial. 0000036243 00000 n
In its basic form, the Chinese remainder theorem will determine a number p p that, when divided by some given divisors, leaves given remainders. //]]>. %PDF-1.3 0000007248 00000 n
Algebraic version. Lecture 4 : Conditional Probability and . @8hua
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YAq,_&''M$%NUpqgEny y1@_?8C}zR"$,n|*5ms3wpSaMN/Zg!bHC{p\^8L E7DGfz8}V2Yt{~ f:2 KG"8_o+ Factor theorem is frequently linked with the remainder theorem, therefore do not confuse both. According to factor theorem, if f(x) is a polynomial of degree n 1 and a is any real number then, (x-a) is a factor of f(x), if f(a)=0. Let be a closed rectangle with (,).Let : be a function that is continuous in and Lipschitz continuous in .Then, there exists some > 0 such that the initial value problem = (, ()), =. l}e4W[;E#xmX$BQ a3b8 7a10b4 +2a5b2 a 3 b 8 7 a 10 b 4 + 2 a 5 b 2 Solution. endobj Now we will study a theorem which will help us to determine whether a polynomial q(x) is a factor of a polynomial p(x) or not without doing the actual division. Substitute the values of x in the equation f(x)= x2+ 2x 15, Since the remainders are zero in the two cases, therefore (x 3) and (x + 5) are factors of the polynomial x2+2x -15. Theorem. 3 0 obj
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The factor theorem enables us to factor any polynomial by testing for different possible factors. 2~% cQ.L 3K)(n}^
]u/gWZu(u$ZP(FmRTUs!k `c5@*lN~ Use synthetic division to divide \(5x^{3} -2x^{2} +1\) by \(x-3\). The Factor Theorem is frequently used to factor a polynomial and to find its roots. 7 years ago.
Example 1 Divide x3 4x2 5x 14 by x 2 Start by writing the problem out in long division form x 2 x3 4x2 5x 14 Now we divide the leading terms: 3 yx 2. pdf, 43.86 MB. 0000006280 00000 n
That being said, lets see what the Remainder Theorem is. We have grown leaps and bounds to be the best Online Tuition Website in India with immensely talented Vedantu Master Teachers, from the most reputed institutions. Attempt to factor as usual (This is quite tricky for expressions like yours with huge numbers, but it is easier than keeping the a coeffcient in.) Proof APTeamOfficial. This shouldnt surprise us - we already knew that if the polynomial factors it reveals the roots. CCore ore CConceptoncept The Factor Theorem A polynomial f(x) has a factor x k if and only if f(k) = 0. It also means that \(x-3\) is not a factor of \(5x^{3} -2x^{2} +1\). It is a special case of a polynomial remainder theorem. And that is the solution: x = 1/2. For example, when constant coecients a and b are involved, the equation may be written as: a dy dx +by = Q(x) In our standard form this is: dy dx + b a y = Q(x) a with an integrating factor of . Factor four-term polynomials by grouping. This gives us a way to find the intercepts of this polynomial. endobj
An example to this would will dx/dy=xz+y, which can also be fixed usage an Laplace transform. window.__mirage2 = {petok:"_iUEwVe.LVVWL1qoF4bc2XpSFh1TEoslSEscivdbGzk-31536000-0"}; is used when factoring the polynomials completely. As result,h(-3)=0 is the only one satisfying the factor theorem. Where can I get study notes on Algebra? Finally, it is worth the time to trace each step in synthetic division back to its corresponding step in long division. To find the polynomial factors of the polynomial according to the factor theorem, the outcome of dividing a polynomialf(x) by (x-c) isf(c)=0. Here we will prove the factor theorem, according to which we can factorise the polynomial. <<19b14e1e4c3c67438c5bf031f94e2ab1>]>>
Solution: p (x)= x+4x-2x+5 Divisor = x-5 p (5) = (5) + 4 (5) - 2 (5) +5 = 125 + 100 - 10 + 5 = 220 Example 2: What would be the remainder when you divide 3x+15x-45 by x-15? Is Factor Theorem and Remainder Theorem the Same? In this article, we will look at a demonstration of the Factor Theorem as well as examples with answers and practice problems. Notice that if the remainder p(a) = 0 then (x a) fully divides into p(x), i.e. For example, 5 is a factor of 30 because when 30 is divided by 5, the quotient is 6, which a whole number and the remainder is zero. 0000018505 00000 n
xTj0}7Q^u3BK The polynomial remainder theorem is an example of this. Note this also means \(4x^{4} -4x^{3} -11x^{2} +12x-3=4\left(x-\dfrac{1}{2} \right)\left(x-\dfrac{1}{2} \right)\left(x-\sqrt{3} \right)\left(x+\sqrt{3} \right)\). We will study how the Factor Theorem is related to the Remainder Theorem and how to use the theorem to factor and find the roots of a polynomial equation. <>stream In the last section we saw that we could write a polynomial as a product of factors, each corresponding to a horizontal intercept. Let k = the 90th percentile. The theorem is commonly used to easily help factorize polynomials while skipping the use of long or synthetic division. Factor Theorem Definition Proof Examples and Solutions In algebra factor theorem is used as a linking factor and zeros of the polynomials and to loop the roots. Now, multiply that \(x^{2}\) by \(x-2\) and write the result below the dividend. %PDF-1.7 xb```b````e`jfc@ >+6E ICsf\_TM?b}.kX2}/m9-1{qHKK'q)>8utf {::@|FQ(I&"a0E jt`(.p9bYxY.x9 gvzp1bj"X0([V7e%R`K4$#Y@"V 1c/
Example: For a curve that crosses the x-axis at 3 points, of which one is at 2. As discussed in the introduction, a polynomial f (x) has a factor (x-a), if and only if, f (a) = 0. Solution: The ODE is y0 = ay + b with a = 2 and b = 3. Then "bring down" the first coefficient of the dividend. Since the remainder is zero, \(x+2\) is a factor of \(x^{3} +8\). Consider a function f (x). << /Length 5 0 R /Filter /FlateDecode >> Now, the obtained equation is x 2 + (b/a) x + c/a = 0 Step 2: Subtract c/a from both the sides of quadratic equation x 2 + (b/a) x + c/a = 0. Determine whetherx+ 1 is a factor of the polynomial 3x4+x3x2+ 3x+ 2, Substitute x = -1 in the equation; 3x4+x3x2+ 3x+ 2. 3(1)4 + (1)3 (1)2 +3(1) + 2= 3(1) + (1) 1 3 + 2 = 0Therefore,x+ 1 is a factor of 3x4+x3x2+ 3x+ 2, Check whether 2x + 1 is a factor of the polynomial 4x3+ 4x2 x 1. 0000001219 00000 n
This is generally used the find roots of polynomial equations. 2. Example: For a curve that crosses the x-axis at 3 points, of which one is at 2. xbbRe`b``3
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Example 1 Solve for x: x3 + 5x2 - 14x = 0 Solution x(x2 + 5x - 14) = 0 \ x(x + 7)(x - 2) = 0 \ x = 0, x = 2, x = -7 Type 2 - Grouping terms With this type, we must have all four terms of the cubic expression. Therefore, the solutions of the function are -3 and 2. Factor trinomials (3 terms) using "trial and error" or the AC method. For problems 1 - 4 factor out the greatest common factor from each polynomial. If f (1) = 0, then (x-1) is a factor of f (x). The online portal, Vedantu.com offers important questions along with answers and other very helpful study material on Factor Theorem, which have been formulated in a well-structured, well researched, and easy to understand manner. Factor Theorem is a special case of Remainder Theorem. (ii) Solution : 2x 4 +9x 3 +2x 2 +10x+15. 1)View SolutionHelpful TutorialsThe factor theorem Click here to see the [] 0000001255 00000 n
Also, we can say, if (x-a) is a factor of polynomial f(x), then f(a) = 0. The following statements are equivalent for any polynomial f(x). The remainder calculator calculates: The remainder theorem calculator displays standard input and the outcomes. Solved Examples 1. 0000003108 00000 n
Consider another case where 30 is divided by 4 to get 7.5. 1. Factor theorem is a method that allows the factoring of polynomials of higher degrees. Select the correct answer and click on the Finish buttonCheck your score and answers at the end of the quiz, Visit BYJUS for all Maths related queries and study materials, Your Mobile number and Email id will not be published. This follows that (x+3) and (x-2) are the polynomial factors of the function. If you find the two values, you should get (y+16) (y-49). Theorem 41.4 Let f (t) and g (t) be two elements in PE with Laplace transforms F (s) and G (s) such that F (s) = G (s) for some s > a. Divide by the integrating factor to get the solution. The factor theorem can be used as a polynomial factoring technique. (Refer to Rational Zero The Factor Theorem is said to be a unique case consideration of the polynomial remainder theorem. xK$7+\\
a2CKRU=V2wO7vfZ:ym{5w3_35M4CknL45nn6R2uc|nxz49|y45gn`f0hxOcpwhzs}& @{zrn'GP/2tJ;M/`&F%{Xe`se+}hsx Each of these terms was obtained by multiplying the terms in the quotient, \(x^{2}\), 6x and 7, respectively, by the -2 in \(x - 2\), then by -1 when we changed the subtraction to addition. 5-a-day GCSE 9-1; 5-a-day Primary; 5-a-day Further Maths; 5-a-day GCSE A*-G; 5-a-day Core 1; More. The Chinese remainder theorem is a theorem which gives a unique solution to simultaneous linear congruences with coprime moduli. has a unique solution () on the interval [, +].. If f (-3) = 0 then (x + 3) is a factor of f (x). According to the Integral Root Theorem, the possible rational roots of the equation are factors of 3. We have constructed a synthetic division tableau for this polynomial division problem. startxref
Finally, take the 2 in the divisor times the 7 to get 14, and add it to the -14 to get 0. So let us arrange it first: Thus! Find out whether x + 1 is a factor of the below-given polynomial. xYr5}Wqu$*(&&^'CK.TEj>ju>_^Mq7szzJN2/R%/N?ivKm)mm{Y{NRj`|3*-,AZE"_F t! Factor theorem assures that a factor (x M) for each root is r. The factor theorem does not state there is only one such factor for each root. The steps are given below to find the factors of a polynomial using factor theorem: Step 1 : If f(-c)=0, then (x+ c) is a factor of the polynomial f(x). The method works for denominators with simple roots, that is, no repeated roots are allowed. stream 0000002952 00000 n
But, before jumping into this topic, lets revisit what factors are. Step 1: Remove the load resistance of the circuit. Factor Theorem - Examples and Practice Problems The Factor Theorem is frequently used to factor a polynomial and to find its roots. Now that you understand how to use the Remainder Theorem to find the remainder of polynomials without actual division, the next theorem to look at in this article is called the Factor Theorem. 0
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There is another way to define the factor theorem. To test whether (x+1) is a factor of the polynomial or not, we can start by writing in the following way: Now, we test whetherf(c)=0 according to the factor theorem: $$f(-1) = 4{(-1)}^3 2{(-1) }^2+ 6(-1) + 8$$. 4.8 Type I We add this to the result, multiply 6x by \(x-2\), and subtract. We conclude that the ODE has innitely many solutions, given by y(t) = c e2t 3 2, c R. Since we did one integration, it is Therefore, (x-2) should be a factor of 2x3x27x+2. 2. factor the polynomial (review the Steps for Factoring if needed) 3. use Zero Factor Theorem to solve Example 1: Solve the quadratic equation s w T2 t= s u T for T and enter exact answers only (no decimal approximations). If f(x) is a polynomial whose graph crosses the x-axis at x=a, then (x-a) is a factor of f(x). xb```b``;X,s6
y Example: Fully factor x 4 3x 3 7x 2 + 15x + 18. Let us take the following: 5 is a factor of 20 since, when we divide 20 by 5, we get the whole number 4 and there is no remainder. Furthermore, the coefficients of the quotient polynomial match the coefficients of the first three terms in the last row, so we now take the plunge and write only the coefficients of the terms to get. px. There is one root at x = -3. -@G5VLpr3jkdHN`RVkCaYsE=vU-O~v!)_>0|7j}iCz/)T[u
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We provide you year-long structured coaching classes for CBSE and ICSE Board & JEE and NEET entrance exam preparation at affordable tuition fees, with an exclusive session for clearing doubts, ensuring that neither you nor the topics remain unattended. Bayes' Theorem is a truly remarkable theorem. The following examples are solved by applying the remainder and factor theorems. It is a theorem that links factors and zeros of the polynomial. Note that by arranging things in this manner, each term in the last row is obtained by adding the two terms above it. Synthetic Division Since dividing by x c is a way to check if a number is a zero of the polynomial, it would be nice to have a faster way to divide by x c than having to use long division every time. integer roots, a theorem about the equality of two polynomials, theorems related to the Euclidean Algorithm for finding the of two polynomials, and theorems about the Partial Fraction!"# Decomposition of a rational function and Descartes's Rule of Signs. 0000017145 00000 n
Show Video Lesson Hence,(x c) is a factor of the polynomial f (x). What is the factor of 2x3x27x+2? The factor theorem can produce the factors of an expression in a trial and error manner. the Pandemic, Highly-interactive classroom that makes Comment 2.2. The quotient is \(x^{2} -2x+4\) and the remainder is zero. In other words, any time you do the division by a number (being a prospective root of the polynomial) and obtain a remainder as zero (0) in the synthetic division, this indicates that the number is surely a root, and hence "x minus (-) the number" is a factor. 0000004105 00000 n
If you get the remainder as zero, the factor theorem is illustrated as follows: The polynomial, say f(x) has a factor (x-c) if f(c)= 0, where f(x) is a polynomial of degree n, where n is greater than or equal to 1 for any real number, c. Apart from factor theorem, there are other methods to find the factors, such as: Factor theorem example and solution are given below. Further Maths; Practice Papers . 2 0 obj f (1) = 3 (1) 4 + (1) 3 (1)2 +3 (1) + 2, Hence, we conclude that (x + 1) is a factor of f (x). stream
Now Before getting to know the Factor Theorem in-depth and what it means, it is imperative that you completely understand the Remainder Theorem and what factors are first. 0000012726 00000 n
Start by writing the problem out in long division form. Some bits are a bit abstract as I designed them myself. Consider a polynomial f (x) of degreen 1. 0000002794 00000 n
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Write the equation in standard form. Find the roots of the polynomial 2x2 7x + 6 = 0. Then f is constrained and has minimal and maximum values on D. In other terms, there are points xm, aM D such that f (x_ {m})\leq f (x)\leq f (x_ {M}) \)for each feasible point of x\inD -----equation no.01. 0000002157 00000 n
The divisor is (x - 3). Therefore, we can write: f(x) is the target polynomial, whileq(x) is the quotient polynomial. ( t \right) = 2t - {t^2} - {t^3}\) on \(\left[ { - 2,1} \right]\) Solution; For problems 3 & 4 determine all the number(s) c which satisfy the . << /Type /Page /Parent 3 0 R /Resources 6 0 R /Contents 4 0 R /MediaBox [0 0 595 842] Example: For a curve that crosses the x-axis at 3 points, of which one is at 2. This doesnt factor nicely, but we could use the quadratic formula to find the remaining two zeros. startxref
Learn Exam Concepts on Embibe Different Types of Polynomials Steps for Solving Network using Maximum Power Transfer Theorem. u^N{R YpUF_d="7/v(QibC=S&n\73jQ!f.Ei(hx-b_UG A power series may converge for some values of x, but diverge for other 1. Whereas, the factor theorem makes aware that if a is a zero of a polynomial f(x), then (xM) is a factor of f(M), and vice-versa. >zjs(f6hP}U^=`W[wy~qwyzYx^Pcq~][+n];ER/p3 i|7Cr*WOE|%Z{\B| \[x^{3} +8=(x+2)\left(x^{2} -2x+4\right)\nonumber \]. 6 0 obj 0000002874 00000 n
Determine whether (x+2) is a factor of the polynomial $latex f(x) = {x}^2 + 2x 4$. 6x7 +3x4 9x3 6 x 7 + 3 x 4 9 x 3 Solution. Solution: Example 7: Show that x + 1 and 2x - 3 are factors of 2x 3 - 9x 2 + x + 12. 0000003905 00000 n
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:/m5`!t *n-YsJ"M'#M vklF._K6"z#Y=xJ5KmS (|\6rg#gM Therefore, we write in the following way: Now, we can use the factor theorem to test whetherf(c)=0: Sincef(-3) is equal to zero, this means that (x +3) is a polynomial factor. Factor Theorem. We use 3 on the left in the synthetic division method along with the coefficients 1,2 and -15 from the given polynomial equation. Examples Example 4 Using the factor theorem, which of the following are factors of 213 Solution Let P(x) = 3x2 2x + 3 3x2 Therefore, Therefore, c. PG) . Likewise, 3 is not a factor of 20 because, when we are 20 divided by 3, we have 6.67, which is not a whole number. 0000030369 00000 n
xw`g. 5 0 obj The functions y(t) = ceat + b a, with c R, are solutions. We will not prove Euler's Theorem here, because we do not need it. Factor P(x) = 6x3 + x2 15x + 4 Solution Note that the factors of 4 are 1,-1, 2,-2,4,-4, and the positive factors of 6 are 1,2,3,6. All functions considered in this . @\)Ta5 Multiply by the integrating factor. 2 - 3x + 5 . Sincef(-1) is not equal to zero, (x +1) is not a polynomial factor of the function. Go through once and get a clear understanding of this theorem. On the other hand, the Factor theorem makes us aware that if a is a zero of a polynomial f(x), then (xM) is a factor of f(M), and vice-versa. ]p:i Y'_v;H9MzkVrYz4z_Jj[6z{~#)w2+0Qz)~kEaKD;"Q?qtU$PB*(1
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UL[&^}]&W's/92wng5*@Lp*`qX2c2#UY+>%O! If f(x) is a polynomial and f(a) = 0, then (x-a) is a factor of f(x). DlE:(u;_WZo@i)]|[AFp5/{TQR
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/Cs1 7 0 R >> /Font << /TT1 8 0 R /TT2 10 0 R /TT3 13 0 R >> /XObject << /Im1 pdf, 283.06 KB. Proof of the factor theorem Let's start with an example. Yg+uMZbKff[4@H$@$Yb5CdOH#
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hOgprp&HH@M`eAOo_N&zAiA [-_!G !0{X7wn-~A# @(8q"sd7Ml\LQ'. The factor theorem tells us that if a is a zero of a polynomial f ( x), then ( x a) is a factor of f ( x) and vice-versa. Maths is an all-important subject and it is necessary to be able to practice some of the important questions to be able to score well. From the previous example, we know the function can be factored as \(h(x)=\left(x-2\right)\left(x^{2} +6x+7\right)\). x2(26x)+4x(412x) x 2 ( 2 6 x . 0000004161 00000 n
Why did we let g(x) = e xf(x), involving the integrant factor e ? When we divide a polynomial, \(p(x)\) by some divisor polynomial \(d(x)\), we will get a quotient polynomial \(q(x)\) and possibly a remainder \(r(x)\). So, (x+1) is a factor of the given polynomial. Where f(x) is the target polynomial and q(x) is the quotient polynomial. This tells us that 90% of all the means of 75 stress scores are at most 3.2 and 10% are at least 3.2. Use factor theorem to show that is a factor of (2) 5. Find the remainder when 2x3+3x2 17 x 30 is divided by each of the following: (a) x 1 (b) x 2 (c) x 3 (d) x +1 (e) x + 2 (f) x + 3 Factor Theorem: If x = a is substituted into a polynomial for x, and the remainder is 0, then x a is a factor of the . If there is more than one solution, separate your answers with commas. So let us arrange it first: Therefore, (x-2) should be a factor of 2x, NCERT Solutions for Class 12 Business Studies, NCERT Solutions for Class 11 Business Studies, NCERT Solutions for Class 10 Social Science, NCERT Solutions for Class 9 Social Science, NCERT Solutions for Class 8 Social Science, CBSE Previous Year Question Papers Class 12, CBSE Previous Year Question Papers Class 10. Section 1.5 : Factoring Polynomials. Hence, or otherwise, nd all the solutions of . Theorem 2 (Euler's Theorem). Resource on the Factor Theorem with worksheet and ppt. endobj 6. This tells us \(x^{3} +4x^{2} -5x-14\) divided by \(x-2\) is \(x^{2} +6x+7\), with a remainder of zero. Rewrite the left hand side of the . We are going to test whether (x+2) is a factor of the polynomial or not. It is a theorem that links factors and, As discussed in the introduction, a polynomial f(x) has a factor (x-a), if and only if, f(a) = 0. It is important to note that it works only for these kinds of divisors. Therefore, according to this theorem, if the remainder of a division is equal to zero, in that case,(x - M) should be a factor, whereas if the remainder of such a division is not 0, in that case,(x - M) will not be a factor. Concerning division, a factor is an expression that, when a further expression is divided by this factor, the remainder is equal to zero (0). Our quotient is \(q(x)=5x^{2} +13x+39\) and the remainder is \(r(x) = 118\). The horizontal intercepts will be at \((2,0)\), \(\left(-3-\sqrt{2} ,0\right)\), and \(\left(-3+\sqrt{2} ,0\right)\). If \(p(c)=0\), then the remainder theorem tells us that if p is divided by \(x-c\), then the remainder will be zero, which means \(x-c\) is a factor of \(p\). endobj The factor theorem states that: "If f (x) is a polynomial and a is a real number, then (x - a) is a factor of f (x) if f (a) = 0.". Lets re-work our division problem using this tableau to see how it greatly streamlines the division process. Thus the factor theorem states that a polynomial has a factor if and only if: The polynomial x - M is a factor of the polynomial f(x) if and only if f (M) = 0. Let f : [0;1] !R be continuous and R 1 0 f(x)dx . 0000001806 00000 n
If \(x-c\) is a factor of the polynomial \(p\), then \(p(x)=(x-c)q(x)\) for some polynomial \(q\). Welcome; Videos and Worksheets; Primary; 5-a-day. Factor Theorem states that if (a) = 0 in this case, then the binomial (x - a) is a factor of polynomial (x). Since \(x=\dfrac{1}{2}\) is an intercept with multiplicity 2, then \(x-\dfrac{1}{2}\) is a factor twice. Use synthetic division to divide by \(x-\dfrac{1}{2}\) twice. Without this Remainder theorem, it would have been difficult to use long division and/or synthetic division to have a solution for the remainder, which is difficult time-consuming. It is one of the methods to do the factorisation of a polynomial. 0000000016 00000 n
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